What is x(3x-18)(6x-48)>= 0 ?

The solution to x(3x-18)(6x-48)>= 0 is 0 = 8

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x(3x-18)(6x-48)>= 0

x (3 x - 18) (6 x - 48) \geq 0

0 \leq x \leq 6 or x \geq 8

Solution steps

x (3 x - 18) (6 x - 48) \geq 0

Rewrite in standard form

x^{3} - 14 x^{2} + 48 x \geq 0

Factor

x^{3} - 14 x^{2} + 48 x : x (x - 6) (x - 8)

x (x - 6) (x - 8) \geq 0

Identify the intervals

0 \leq x \leq 6 or x \geq 8

x^{2} + 2 x + 18 = 0

\frac{3 z ^{2} - 13 z + 4}{z ^{4} - 2 z ^{3} - 8 z ^{2}}

9 x^{7} y^{5} - 3 x^{2} y^{6}

3 x^{2} - 42 x + 147

z + 3 (z + 7) = - 5

What is x(3x-18)(6x-48)>= 0 ?
The solution to x(3x-18)(6x-48)>= 0 is 0<= x<= 6\lor x>= 8