What are the solutions to the equation log_{3}(3)x^2+log_{3}(3)=2 ?

The solutions to the equation log_{3}(3)x^2+log_{3}(3)=2 are x=1,x=-1

Find the zeros of log_{3}(3)x^2+log_{3}(3)=2

The zeros of log_{3}(3)x^2+log_{3}(3)=2 are x=1,x=-1

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lo g_{3} (3) x^{2} + lo g_{3} (3) = 2

x = 1, x = - 1

Solution steps

lo g_{3} (3) x^{2} + lo g_{3} (3) = 2

Move

lo g_{3} (3)

to the right side

lo g_{3} (3) x^{2} = 1

Simplify

lo g_{3} (3) : 1

1 \cdot x^{2} = 1

Simplify

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

3 a^{2} + 4 a - 4

\frac{8 ^{4}}{4 ^{4}}

2 (3 - x)^{2} + \frac{1}{2} = \frac{5}{2}

3 x^{2} + 7 x + 2 = 0

4 x^{2} - 13 = 0

What are the solutions to the equation log_{3}(3)x^2+log_{3}(3)=2 ?
The solutions to the equation log_{3}(3)x^2+log_{3}(3)=2 are x=1,x=-1
Find the zeros of log_{3}(3)x^2+log_{3}(3)=2
The zeros of log_{3}(3)x^2+log_{3}(3)=2 are x=1,x=-1