What are the solutions to the equation 10d^2-29d+10=0 ?

The solutions to the equation 10d^2-29d+10=0 are d= 5/2 ,d= 2/5

Find the zeros of 10d^2-29d+10=0

The zeros of 10d^2-29d+10=0 are d= 5/2 ,d= 2/5

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10 d^{2} - 29 d + 10 = 0

d = \frac{5}{2}, d = \frac{2}{5}

Decimal Notation

d = 2.5, d = 0.4

Solution steps

10 d^{2} - 29 d + 10 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- ( - 29 ) \pm ( - 29 ) ^{2} - 4 \cdot 10 \cdot 10}{2 \cdot 10}

(- 29)^{2} - 4 \cdot 10 \cdot 10 = 21

d_{1, 2} = \frac{- ( - 29 ) \pm 21}{2 \cdot 10}

Separate the solutions

d_{1} = \frac{- ( - 29 ) + 21}{2 \cdot 10}, d_{2} = \frac{- ( - 29 ) - 21}{2 \cdot 10}

d = \frac{- ( - 29 ) + 21}{2 \cdot 10} : \frac{5}{2}

d = \frac{- ( - 29 ) - 21}{2 \cdot 10} : \frac{2}{5}

The solutions to the quadratic equation are:

d = \frac{5}{2}, d = \frac{2}{5}

7 p^{2} - 38 p - 24 = 0

\frac{5}{b ^{- 2}}

4 x^{2} + 29 = - 20 x

(2 + 3 i)^{2} + (2 - 3 i)^{2}

2 x - 3 (x + 5) = 2 x - (x + 3)

What are the solutions to the equation 10d^2-29d+10=0 ?
The solutions to the equation 10d^2-29d+10=0 are d= 5/2 ,d= 2/5
Find the zeros of 10d^2-29d+10=0
The zeros of 10d^2-29d+10=0 are d= 5/2 ,d= 2/5