What are the solutions to the equation 0=x^2+4x-3 ?

The solutions to the equation 0=x^2+4x-3 are x=-2+sqrt(7),x=-2-sqrt(7)

Find the zeros of 0=x^2+4x-3

The zeros of 0=x^2+4x-3 are x=-2+sqrt(7),x=-2-sqrt(7)

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0 = x^{2} + 4 x - 3

x = - 2 + 7, x = - 2 - 7

Decimal Notation

x = 0.64575 \dots, x = - 4.64575 \dots

Solution steps

0 = x^{2} + 4 x - 3

Switch sides

x^{2} + 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 3) = 27

x_{1, 2} = \frac{- 4 \pm 2 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 7}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 7}{2 \cdot 1}

x = \frac{- 4 + 2 7}{2 \cdot 1} : - 2 + 7

x = \frac{- 4 - 2 7}{2 \cdot 1} : - 2 - 7

The solutions to the quadratic equation are:

x = - 2 + 7, x = - 2 - 7

- 17 x - 8 \leq - 25

5 z^{2} + 20 = 0

- 3 y \leq 15

\frac{( 2 + 3 h ) ^{2} - 4}{h}

x^{2} - 6 x = 1

What are the solutions to the equation 0=x^2+4x-3 ?
The solutions to the equation 0=x^2+4x-3 are x=-2+sqrt(7),x=-2-sqrt(7)
Find the zeros of 0=x^2+4x-3
The zeros of 0=x^2+4x-3 are x=-2+sqrt(7),x=-2-sqrt(7)