What are the solutions to the equation x^2+4x-7=0 ?

The solutions to the equation x^2+4x-7=0 are x=-2+sqrt(11),x=-2-sqrt(11)

Find the zeros of x^2+4x-7=0

The zeros of x^2+4x-7=0 are x=-2+sqrt(11),x=-2-sqrt(11)

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x^{2} + 4 x - 7 = 0

x = - 2 + 11, x = - 2 - 11

Decimal Notation

x = 1.31662 \dots, x = - 5.31662 \dots

Solution steps

x^{2} + 4 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 7) = 211

x_{1, 2} = \frac{- 4 \pm 2 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 11}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 11}{2 \cdot 1}

x = \frac{- 4 + 2 11}{2 \cdot 1} : - 2 + 11

x = \frac{- 4 - 2 11}{2 \cdot 1} : - 2 - 11

The solutions to the quadratic equation are:

x = - 2 + 11, x = - 2 - 11

x (x - 2) = 8

2 x + 14 = x + 6

t^{2} - t - 20 = 0

k^{2} = 4 k

5 \cdot \frac{1}{3}

What are the solutions to the equation x^2+4x-7=0 ?
The solutions to the equation x^2+4x-7=0 are x=-2+sqrt(11),x=-2-sqrt(11)
Find the zeros of x^2+4x-7=0
The zeros of x^2+4x-7=0 are x=-2+sqrt(11),x=-2-sqrt(11)