What is (6a^{4/3}*2b^{1/4})(a^{1/3}*4b^{1/8}) ?

The solution to (6a^{4/3}*2b^{1/4})(a^{1/3}*4b^{1/8}) is 48a^{5/3}b^{3/8}

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simplify (6a^{4/3}2b^{1/4})(a^{1/3}4b^{1/8})

simplify

(6 a^{\frac{4}{3}} \cdot 2 b^{\frac{1}{4}}) (a^{\frac{1}{3}} \cdot 4 b^{\frac{1}{8}})

48 a^{\frac{5}{3}} b^{\frac{3}{8}}

Solution steps

(6 a^{\frac{4}{3}} \cdot 2 b^{\frac{1}{4}}) (a^{\frac{1}{3}} \cdot 4 b^{\frac{1}{8}})

Multiply the numbers:

6 \cdot 2 = 12

= 12 a^{\frac{4}{3}} b^{\frac{1}{4}} a^{\frac{1}{3}} \cdot 4 b^{\frac{1}{8}}

Multiply the numbers:

12 \cdot 4 = 48

= 48 a^{\frac{4}{3}} b^{\frac{1}{4}} a^{\frac{1}{3}} b^{\frac{1}{8}}

Simplify

a^{\frac{4}{3}} a^{\frac{1}{3}} : a^{\frac{5}{3}}

= 48 a^{\frac{5}{3}} b^{\frac{1}{4}} b^{\frac{1}{8}}

Simplify

b^{\frac{1}{4}} b^{\frac{1}{8}} : b^{\frac{3}{8}}

= 48 a^{\frac{5}{3}} b^{\frac{3}{8}}

\frac{8 !}{4 ! 4 !}

v^{2} = 0 + 2 \cdot 2.11 \cdot 5.84

\frac{19}{3} - \frac{2}{8}

2 x^{3} + 7 x^{2} y - 4 x y^{2}

11 p^{2} - 17 p - 20 = p^{2}

What is (6a^{4/3}*2b^{1/4})(a^{1/3}*4b^{1/8}) ?
The solution to (6a^{4/3}*2b^{1/4})(a^{1/3}*4b^{1/8}) is 48a^{5/3}b^{3/8}