What is 2X(8X-1)>= (4X+1)(4X-3) ?

The solution to 2X(8X-1)>= (4X+1)(4X-3) is X>=-1/2

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2X(8X-1)>= (4X+1)(4X-3)

2 X (8 X - 1) \geq (4 X + 1) (4 X - 3)

X \geq - \frac{1}{2}

Interval Notation

[- \frac{1}{2}, \infty)

Decimal Notation

X \geq - 0.5

Solution steps

2 X (8 X - 1) \geq (4 X + 1) (4 X - 3)

Rewrite in standard form

2 X + 1 \geq 0

Move

1

to the right side

2 X \geq - 1

Divide both sides by

2

X \geq - \frac{1}{2}

9 x - 1 < 34 (16 x - 2)

6 [4 - 2 (7 y - 1)] = 8 (13 - 8 y)

3 - \frac{2 x}{3} < \frac{1}{2} + \frac{3 x}{4}

5 + 3

(\frac{2}{5} m^{2} n + \frac{1}{3} mn) (\frac{3}{2} m^{2} n + 2 m n^{- 3})

What is 2X(8X-1)>= (4X+1)(4X-3) ?
The solution to 2X(8X-1)>= (4X+1)(4X-3) is X>=-1/2