What are the solutions to the equation 2x^2+2x+1=0 ?

The solutions to the equation 2x^2+2x+1=0 are x=-1/2+i 1/2 ,x=-1/2-i 1/2

Find the zeros of 2x^2+2x+1=0

The zeros of 2x^2+2x+1=0 are x=-1/2+i 1/2 ,x=-1/2-i 1/2

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2 x^{2} + 2 x + 1 = 0

x = - \frac{1}{2} + i \frac{1}{2}, x = - \frac{1}{2} - i \frac{1}{2}

Solution steps

2 x^{2} + 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 \cdot 1}{2 \cdot 2}

Simplify

2^{2} - 4 \cdot 2 \cdot 1 : 2 i

x_{1, 2} = \frac{- 2 \pm 2 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 2 + 2 i}{2 \cdot 2}, x_{2} = \frac{- 2 - 2 i}{2 \cdot 2}

x = \frac{- 2 + 2 i}{2 \cdot 2} : - \frac{1}{2} + i \frac{1}{2}

x = \frac{- 2 - 2 i}{2 \cdot 2} : - \frac{1}{2} - i \frac{1}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{1}{2}, x = - \frac{1}{2} - i \frac{1}{2}

(32 x^{- 20} y^{15})^{\frac{4}{5}}

\frac{4 y - 2 y}{2 x y}

∣ x + 2 ∣ + 1 \geq 7

49 a^{2} - 28 a + 4

x^{2} - 3 x - 2 = 0

What are the solutions to the equation 2x^2+2x+1=0 ?
The solutions to the equation 2x^2+2x+1=0 are x=-1/2+i 1/2 ,x=-1/2-i 1/2
Find the zeros of 2x^2+2x+1=0
The zeros of 2x^2+2x+1=0 are x=-1/2+i 1/2 ,x=-1/2-i 1/2