What are the solutions to the equation 21n+12n^2=0 ?

The solutions to the equation 21n+12n^2=0 are n=0,n=-7/4

Find the zeros of 21n+12n^2=0

The zeros of 21n+12n^2=0 are n=0,n=-7/4

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21 n + 12 n^{2} = 0

n = 0, n = - \frac{7}{4}

Decimal

n = 0, n = - 1.75

Solution steps

21 n + 12 n^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

12 n^{2} + 21 n = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 12 \cdot 0}{2 \cdot 12}

2 1^{2} - 4 \cdot 12 \cdot 0 = 21

n_{1, 2} = \frac{- 21 \pm 21}{2 \cdot 12}

Separate the solutions

n_{1} = \frac{- 21 + 21}{2 \cdot 12}, n_{2} = \frac{- 21 - 21}{2 \cdot 12}

n = \frac{- 21 + 21}{2 \cdot 12} : 0

n = \frac{- 21 - 21}{2 \cdot 12} : - \frac{7}{4}

The solutions to the quadratic equation are:

n = 0, n = - \frac{7}{4}

2 x^{2} + 6 = 0

r^{2} - 11 r + 30 = 0

\frac{x - 3 y}{x + y} + \frac{x + 5 y}{x + y}

m^{2} - 4 m - 5

x^{2} + 8 x - 84 = 0

What are the solutions to the equation 21n+12n^2=0 ?
The solutions to the equation 21n+12n^2=0 are n=0,n=-7/4
Find the zeros of 21n+12n^2=0
The zeros of 21n+12n^2=0 are n=0,n=-7/4