What are the solutions to the equation m^2+6m=-5 ?

The solutions to the equation m^2+6m=-5 are m=-1,m=-5

Find the zeros of m^2+6m=-5

The zeros of m^2+6m=-5 are m=-1,m=-5

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m^{2} + 6 m = - 5

m = - 1, m = - 5

Solution steps

m^{2} + 6 m = - 5

Move

5

to the left side

m^{2} + 6 m + 5 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 5 = 4

m_{1, 2} = \frac{- 6 \pm 4}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 6 + 4}{2 \cdot 1}, m_{2} = \frac{- 6 - 4}{2 \cdot 1}

m = \frac{- 6 + 4}{2 \cdot 1} : - 1

m = \frac{- 6 - 4}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

m = - 1, m = - 5

5^{2} + 1^{2} = c^{2}

b^{2} - 64

3 x^{2} - 2 + 7 x = 0

\frac{x}{3} \leq - 4

\frac{( ( x + 2 ) )}{4} - \frac{( x - 2 )}{3} x = x + \frac{( 2 ( x - 3 ) )}{3} x

What are the solutions to the equation m^2+6m=-5 ?
The solutions to the equation m^2+6m=-5 are m=-1,m=-5
Find the zeros of m^2+6m=-5
The zeros of m^2+6m=-5 are m=-1,m=-5