What is (2/3)^{-5}(2/3)^4 ?

The solution to (2/3)^{-5}(2/3)^4 is 3/2

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simplify (2/3)^{-5}(2/3)^4

simplify

(\frac{2}{3})^{- 5} (\frac{2}{3})^{4}

\frac{3}{2}

Decimal Notation

1.5

Solution steps

(\frac{2}{3})^{- 5} (\frac{2}{3})^{4}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

(\frac{2}{3})^{- 5} (\frac{2}{3})^{4} = (\frac{2}{3})^{- 5 + 4}

= (\frac{2}{3})^{- 5 + 4}

Add/Subtract the numbers:

- 5 + 4 = - 1

= (\frac{2}{3})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

(\frac{2}{3})^{- 1} = \frac{1}{\frac{2}{3}}

= \frac{1}{\frac{2}{3}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{3}{2}

\frac{( 4 q h ^{- 3} ) ^{- 2}}{12 q ^{8} h ^{8}}

- 6 (3 z + 3) < - 2 (5 z - 4)

q^{2} + 18 q + 81 = 0

(x + 4) (x - 5) > 0

\frac{y ^{5}}{x ^{- 2} x ^{- 3} y ^{- 8}}