What are the solutions to the equation 3x^2-2x-18=0 ?

The solutions to the equation 3x^2-2x-18=0 are x=(1+sqrt(55))/3 ,x=(1-sqrt(55))/3

Find the zeros of 3x^2-2x-18=0

The zeros of 3x^2-2x-18=0 are x=(1+sqrt(55))/3 ,x=(1-sqrt(55))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 2 x - 18 = 0

x = \frac{1 + 55}{3}, x = \frac{1 - 55}{3}

Decimal Notation

x = 2.80539 \dots, x = - 2.13873 \dots

Solution steps

3 x^{2} - 2 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 ( - 18 )}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 (- 18) = 255

x_{1, 2} = \frac{- ( - 2 ) \pm 2 55}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 55}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 2 55}{2 \cdot 3}

x = \frac{- ( - 2 ) + 2 55}{2 \cdot 3} : \frac{1 + 55}{3}

x = \frac{- ( - 2 ) - 2 55}{2 \cdot 3} : \frac{1 - 55}{3}

The solutions to the quadratic equation are:

x = \frac{1 + 55}{3}, x = \frac{1 - 55}{3}

16 x^{2} + 16 = 0

4 (6 - 3 x)^{2} + 42 = 43

2 c^{2} + c = 6

- \frac{1}{2} x = 4

5 (- 2 k - 3) + 2 k

What are the solutions to the equation 3x^2-2x-18=0 ?
The solutions to the equation 3x^2-2x-18=0 are x=(1+sqrt(55))/3 ,x=(1-sqrt(55))/3
Find the zeros of 3x^2-2x-18=0
The zeros of 3x^2-2x-18=0 are x=(1+sqrt(55))/3 ,x=(1-sqrt(55))/3