What are the solutions to the equation x^2-4x+2=0 ?

The solutions to the equation x^2-4x+2=0 are x=2+sqrt(2),x=2-sqrt(2)

Find the zeros of x^2-4x+2=0

The zeros of x^2-4x+2=0 are x=2+sqrt(2),x=2-sqrt(2)

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x^{2} - 4 x + 2 = 0

x = 2 + 2, x = 2 - 2

Decimal Notation

x = 3.41421 \dots, x = 0.58578 \dots

Solution steps

x^{2} - 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 2 = 22

x_{1, 2} = \frac{- ( - 4 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 2}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 2}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 2}{2 \cdot 1} : 2 + 2

x = \frac{- ( - 4 ) - 2 2}{2 \cdot 1} : 2 - 2

The solutions to the quadratic equation are:

x = 2 + 2, x = 2 - 2

11 a^{2} - 4 a^{3}

n^{2} - 12 n + 35

- 4 y + 6 = - 2 (4 y + 11)

a^{2} - 9 a + 8 = 0

What are the solutions to the equation x^2-4x+2=0 ?
The solutions to the equation x^2-4x+2=0 are x=2+sqrt(2),x=2-sqrt(2)
Find the zeros of x^2-4x+2=0
The zeros of x^2-4x+2=0 are x=2+sqrt(2),x=2-sqrt(2)