What is the answer to 3x+2(x-2)+6=2(2x+3)+x-4 ?

The answer to 3x+2(x-2)+6=2(2x+3)+x-4 is True for all x

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3x+2(x-2)+6=2(2x+3)+x-4

3 x + 2 (x - 2) + 6 = 2 (2 x + 3) + x - 4

True for all x

Solution steps

3 x + 2 (x - 2) + 6 = 2 (2 x + 3) + x - 4

Expand

3 x + 2 (x - 2) + 6 : 5 x + 2

Expand

2 (2 x + 3) + x - 4 : 5 x + 2

5 x + 2 = 5 x + 2

Move

2

to the right side

5 x = 5 x

Move

5 x

to the left side

0 = 0

Both sides are equal

True for all x

2 x^{2} + 3 x - 35 = 0

9^{2} + b^{2} = 1 1^{2}

x^{5} - x

x - 5 \cdot x + 2

(64 n^{9})^{\frac{2}{3}}

What is the answer to 3x+2(x-2)+6=2(2x+3)+x-4 ?
The answer to 3x+2(x-2)+6=2(2x+3)+x-4 is True for all x
Solve for x: 3x+2(x-2)+6=2(2x+3)+x-4
The solution is True for all x