What are the solutions to the equation x^2-4x+4=16 ?

The solutions to the equation x^2-4x+4=16 are x=6,x=-2

Find the zeros of x^2-4x+4=16

The zeros of x^2-4x+4=16 are x=6,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 4 x + 4 = 16

x = 6, x = - 2

Solution steps

x^{2} - 4 x + 4 = 16

Move

16

to the left side

x^{2} - 4 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 12) = 8

x_{1, 2} = \frac{- ( - 4 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 8}{2 \cdot 1}

x = \frac{- ( - 4 ) + 8}{2 \cdot 1} : 6

x = \frac{- ( - 4 ) - 8}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 6, x = - 2

\frac{1}{2} (3 x - 1) < \frac{3}{8} (x + 1)

x^{2} + 8 x + 15 \geq 0

x \cdot x^{\frac{2}{3}}

u^{2} - 2 u - 3 = 0

6 x^{2} - 7 x = 2

What are the solutions to the equation x^2-4x+4=16 ?
The solutions to the equation x^2-4x+4=16 are x=6,x=-2
Find the zeros of x^2-4x+4=16
The zeros of x^2-4x+4=16 are x=6,x=-2