What are the solutions to the equation u^2-2u-3=0 ?

The solutions to the equation u^2-2u-3=0 are u=3,u=-1

Find the zeros of u^2-2u-3=0

The zeros of u^2-2u-3=0 are u=3,u=-1

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u^{2} - 2 u - 3 = 0

u = 3, u = - 1

Solution steps

u^{2} - 2 u - 3 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 3) = 4

u_{1, 2} = \frac{- ( - 2 ) \pm 4}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 2 ) + 4}{2 \cdot 1}, u_{2} = \frac{- ( - 2 ) - 4}{2 \cdot 1}

u = \frac{- ( - 2 ) + 4}{2 \cdot 1} : 3

u = \frac{- ( - 2 ) - 4}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

u = 3, u = - 1

6 x^{2} - 7 x = 2

\frac{11 !}{2 ! ( 11 - 2 ) !}

3 x - 4 \geq 5

8 \cdot 5

\frac{( 4 p ^{- 4} q ) ^{- 2}}{10 p q ^{- 3}}

What are the solutions to the equation u^2-2u-3=0 ?
The solutions to the equation u^2-2u-3=0 are u=3,u=-1
Find the zeros of u^2-2u-3=0
The zeros of u^2-2u-3=0 are u=3,u=-1