What is the d/(dy)((y-1)^2(2-y)(y-3)) ?

The d/(dy)((y-1)^2(2-y)(y-3)) is -4y^3+21y^2-34y+17

What is the first d/(dy)((y-1)^2(2-y)(y-3)) ?

The first d/(dy)((y-1)^2(2-y)(y-3)) is -4y^3+21y^2-34y+17

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d y} ((y - 1)^{2} (2 - y) (y - 3))

- 4 y^{3} + 21 y^{2} - 34 y + 17

Solution steps

\frac{d}{d y} ((y - 1)^{2} (2 - y) (y - 3))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = (y - 1)^{2}, g = (2 - y) (y - 3)

= \frac{d}{d y} ((y - 1)^{2}) (2 - y) (y - 3) + \frac{d}{d y} ((2 - y) (y - 3)) (y - 1)^{2}

\frac{d}{d y} ((y - 1)^{2}) = 2 (y - 1)

\frac{d}{d y} ((2 - y) (y - 3)) = - 2 y + 5

= 2 (y - 1) (2 - y) (y - 3) + (- 2 y + 5) (y - 1)^{2}

Simplify

2 (y - 1) (2 - y) (y - 3) + (- 2 y + 5) (y - 1)^{2} : - 4 y^{3} + 21 y^{2} - 34 y + 17

= - 4 y^{3} + 21 y^{2} - 34 y + 17

2 (a + b)^{3} - 8 (a + b)^{2}

(\frac{1}{16})^{3 x - 4} \leq 6 4^{x - 1}

\frac{x - 6}{x + 2} \leq 0

lo g_{\frac{1}{3}} (2)

x^{2} + 5 = - 5 x

What is the d/(dy)((y-1)^2(2-y)(y-3)) ?
The d/(dy)((y-1)^2(2-y)(y-3)) is -4y^3+21y^2-34y+17
What is the first d/(dy)((y-1)^2(2-y)(y-3)) ?
The first d/(dy)((y-1)^2(2-y)(y-3)) is -4y^3+21y^2-34y+17