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Popular >

(1/16)^{3x-4}<= 64^{x-1}

Solution

(\frac{1}{16})^{3 x - 4} \leq 6 4^{x - 1}

Solution

x \geq \frac{11}{9}

+2

Interval Notation

[\frac{11}{9}, \infty)

Decimal Notation

x \geq 1.22222 \dots

Solution steps

(\frac{1}{16})^{3 x - 4} \leq 6 4^{x - 1}

If

f (x) \leq g (x)

then

ln (f (x)) \leq ln (g (x))

ln ((\frac{1}{16})^{3 x - 4}) \leq ln (6 4^{x - 1})

Simplify

ln ((\frac{1}{16})^{3 x - 4}) : - 4 ln (2) (3 x - 4)

Simplify

ln (6 4^{x - 1}) : 6 ln (2) (x - 1)

- 4 ln (2) (3 x - 4) \leq 6 ln (2) (x - 1)

- 4 ln (2) (3 x - 4) \leq 6 ln (2) (x - 1) : x \geq \frac{11}{9}

x \geq \frac{11}{9}

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Frequently Asked Questions (FAQ)

What is (1/16)^{3x-4}<= 64^{x-1} ?
The solution to (1/16)^{3x-4}<= 64^{x-1} is x>= 11/9