What is factor 3x^4-16x^3+29x^2-20x+4 ?

The solution to factor 3x^4-16x^3+29x^2-20x+4 is (x-1)(3x-1)(x-2)^2

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factor 3x^4-16x^3+29x^2-20x+4

factor

3 x^{4} - 16 x^{3} + 29 x^{2} - 20 x + 4

(x - 1) (3 x - 1) (x - 2)^{2}

Solution steps

3 x^{4} - 16 x^{3} + 29 x^{2} - 20 x + 4

Use the rational root theorem

= (x - 1) \frac{3 x ^{4} - 16 x ^{3} + 29 x ^{2} - 20 x + 4}{x - 1}

\frac{3 x ^{4} - 16 x ^{3} + 29 x ^{2} - 20 x + 4}{x - 1} = 3 x^{3} - 13 x^{2} + 16 x - 4

= (x - 1) (3 x^{3} - 13 x^{2} + 16 x - 4)

Factor

3 x^{3} - 13 x^{2} + 16 x - 4 : (3 x - 1) (x - 2) (x - 2)

= (x - 1) (3 x - 1) (x - 2) (x - 2)

Apply exponent rule:

aa = a^{2}

(x - 2) (x - 2) = (x - 2)^{2}

= (x - 1) (3 x - 1) (x - 2)^{2}

3405

x + 5 \leq - 4 x + 5 \leq - 4

x^{2} - 18 x + 85 = 0

\frac{3}{4} \cdot 4 - 1

2 x^{2} - 9 x - 8 = 0

What is factor 3x^4-16x^3+29x^2-20x+4 ?
The solution to factor 3x^4-16x^3+29x^2-20x+4 is (x-1)(3x-1)(x-2)^2