What are the solutions to the equation (x-1)(x-3)=0 ?

The solutions to the equation (x-1)(x-3)=0 are x=1,x=3

Find the zeros of (x-1)(x-3)=0

The zeros of (x-1)(x-3)=0 are x=1,x=3

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(x - 1) (x - 3) = 0

x = 1, x = 3

Solution steps

(x - 1) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x - 3 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 3 = 0 : x = 3

The solutions to the quadratic equation are:

x = 1, x = 3

24 p + 12 - 18 p = 10 + 2 p - 6

∣ h - 0.018 ∣ \leq 0.001

\frac{3}{5} + \frac{7}{15}

\frac{3 - 2 x}{5} < 4 \leq \frac{1 - x}{2}

\frac{0.5 ( 9.1 - 7.3 ) ^{2}}{5.8 + 8.6 - 5.4}

What are the solutions to the equation (x-1)(x-3)=0 ?
The solutions to the equation (x-1)(x-3)=0 are x=1,x=3
Find the zeros of (x-1)(x-3)=0
The zeros of (x-1)(x-3)=0 are x=1,x=3