What are the solutions to the equation y^2-5y=36 ?

The solutions to the equation y^2-5y=36 are y=9,y=-4

Find the zeros of y^2-5y=36

The zeros of y^2-5y=36 are y=9,y=-4

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y^{2} - 5 y = 36

y = 9, y = - 4

Solution steps

y^{2} - 5 y = 36

Move

36

to the left side

y^{2} - 5 y - 36 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 36) = 13

y_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 5 ) + 13}{2 \cdot 1}, y_{2} = \frac{- ( - 5 ) - 13}{2 \cdot 1}

y = \frac{- ( - 5 ) + 13}{2 \cdot 1} : 9

y = \frac{- ( - 5 ) - 13}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

y = 9, y = - 4

(4 a)^{- 3} \cdot a^{- 4}

x^{2} + 7 x = - 12

x^{4} - 3 x^{3} + 3 x^{2} - 3 x + 2

(3 x - 5)^{2} + 7 (3 x - 5) + 12 = 0

∣ 8 - 4 x ∣ \leq 3

What are the solutions to the equation y^2-5y=36 ?
The solutions to the equation y^2-5y=36 are y=9,y=-4
Find the zeros of y^2-5y=36
The zeros of y^2-5y=36 are y=9,y=-4