What are the solutions to the equation 15x^2+58x+48=0 ?

The solutions to the equation 15x^2+58x+48=0 are x=-6/5 ,x=-8/3

Find the zeros of 15x^2+58x+48=0

The zeros of 15x^2+58x+48=0 are x=-6/5 ,x=-8/3

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15 x^{2} + 58 x + 48 = 0

x = - \frac{6}{5}, x = - \frac{8}{3}

Decimal Notation

x = - 1.2, x = - 2.66666 \dots

Solution steps

15 x^{2} + 58 x + 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 58 \pm 5 8 ^{2} - 4 \cdot 15 \cdot 48}{2 \cdot 15}

5 8^{2} - 4 \cdot 15 \cdot 48 = 22

x_{1, 2} = \frac{- 58 \pm 22}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- 58 + 22}{2 \cdot 15}, x_{2} = \frac{- 58 - 22}{2 \cdot 15}

x = \frac{- 58 + 22}{2 \cdot 15} : - \frac{6}{5}

x = \frac{- 58 - 22}{2 \cdot 15} : - \frac{8}{3}

The solutions to the quadratic equation are:

x = - \frac{6}{5}, x = - \frac{8}{3}

7 x^{2} - 9 x - 10

\frac{v}{4} + 2 = - 2

x^{2} = 4 x - 11

4 x^{2} + 8 x = - 4

\frac{x ^{- 4} y ^{- 5} y ^{2}}{x}

What are the solutions to the equation 15x^2+58x+48=0 ?
The solutions to the equation 15x^2+58x+48=0 are x=-6/5 ,x=-8/3
Find the zeros of 15x^2+58x+48=0
The zeros of 15x^2+58x+48=0 are x=-6/5 ,x=-8/3