What is -5|x-4|>=-20 ?

The solution to -5|x-4|>=-20 is 0<= x<= 8

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-5|x-4|>=-20

- 5 ∣ x - 4 ∣ \geq - 20

0 \leq x \leq 8

Interval Notation

[0, 8]

Solution steps

- 5 ∣ x - 4 ∣ \geq - 20

Multiply both sides by

- 1

5 ∣ x - 4 ∣ \leq 20

Divide both sides by

5

∣ x - 4 ∣ \leq 4

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 4 \leq x - 4 \leq 4

x - 4 \geq - 4 and x - 4 \leq 4

x \geq 0 and x \leq 8

Merge Overlapping Intervals

0 \leq x \leq 8

- 3 x^{2} + 4 x - 7 = 0

x + 2 < - 1 or x + 3 \geq 2

x y^{2} - x^{3} y^{5}

(a^{- 5} b^{8} c^{- 12}) (a^{7} b^{- 3} c^{7})

2 x - 1 \leq 3