What are the solutions to the equation 6x^2+6x-72=0 ?

The solutions to the equation 6x^2+6x-72=0 are x=3,x=-4

Find the zeros of 6x^2+6x-72=0

The zeros of 6x^2+6x-72=0 are x=3,x=-4

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6 x^{2} + 6 x - 72 = 0

x = 3, x = - 4

Solution steps

6 x^{2} + 6 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 6 ( - 72 )}{2 \cdot 6}

6^{2} - 4 \cdot 6 (- 72) = 42

x_{1, 2} = \frac{- 6 \pm 42}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 6 + 42}{2 \cdot 6}, x_{2} = \frac{- 6 - 42}{2 \cdot 6}

x = \frac{- 6 + 42}{2 \cdot 6} : 3

x = \frac{- 6 - 42}{2 \cdot 6} : - 4

The solutions to the quadratic equation are:

x = 3, x = - 4

- 2 - (- 8)

3 r^{2} + r + 9 = 2

5 x^{2} + 10 x^{4}

5 z^{2} = 17 z - 14

\frac{( - 2 + 4 i )}{2 i}

What are the solutions to the equation 6x^2+6x-72=0 ?
The solutions to the equation 6x^2+6x-72=0 are x=3,x=-4
Find the zeros of 6x^2+6x-72=0
The zeros of 6x^2+6x-72=0 are x=3,x=-4