What is (\sqrt[3]{-40})^5 ?

The solution to (\sqrt[3]{-40})^5 is -160\sqrt[3]{5^2}

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simplify (\sqrt[3]{-40})^5

simplify

Decimal Notation

- 467.84283 \dots

Solution steps

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

2^{2} = 4

= - 40 \cdot 4 \cdot 5^{\frac{2}{3}}

Multiply the numbers:

- 40 \cdot 4 = - 160

= - 160 \cdot 5^{\frac{2}{3}}

= - 5^{\frac{2}{3}} \cdot 160

x^{2} + x - 2 \leq 0

(8 x)^{2}

x = 0.25 \cdot (1 0^{4} x + 0.8)^{2}

3 x^{2} + 13 x + 10 = 0

1 x + 5 \geq - 16

What is (\sqrt[3]{-40})^5 ?
The solution to (\sqrt[3]{-40})^5 is -160\sqrt[3]{5^2}