What are the solutions to the equation x=0.25*(10^4x+0.8)^2 ?

The solutions to the equation x=0.25*(10^4x+0.8)^2 are x=-3999/50000000

Find the zeros of x=0.25*(10^4x+0.8)^2

The zeros of x=0.25*(10^4x+0.8)^2 are x=-3999/50000000

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x = 0.25 \cdot (1 0^{4} x + 0.8)^{2}

x = - \frac{3999}{50000000}

Decimal Notation

x = - 0.00007998

Solution steps

x = 0.25 (1 0^{4} x + 0.8)^{2}

Expand

0.25 (1 0^{4} x + 0.8)^{2} : 25000000 x^{2} + 4000 x + 0.16

x = 25000000 x^{2} + 4000 x + 0.16

Switch sides

25000000 x^{2} + 4000 x + 0.16 = x

Move

x

to the left side

25000000 x^{2} + 3999 x + 0.16 = 0

Divide both sides by

25000000

\frac{25000000 x ^{2}}{25000000} + \frac{3999 x}{25000000} + \frac{0.16}{25000000} = \frac{0}{25000000}

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + \frac{3999 x}{25000000} + \frac{0.16}{25000000} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- \frac{3999}{25000000} \pm ( \frac{3999}{25000000} ) ^{2} - 4 \cdot 1 \cdot \frac{0.16}{25000000}}{2 \cdot 1}

(\frac{3999}{25000000})^{2} - 4 \cdot 1 \cdot \frac{0.16}{25000000} = \frac{15992001}{2500000 0 ^{2}} - \frac{0.64}{25000000}

x_{1, 2} = \frac{- \frac{3999}{25000000} \pm 0}{2 \cdot 1}

x = \frac{- \frac{3999}{25000000}}{2 \cdot 1}

\frac{- \frac{3999}{25000000}}{2 \cdot 1} = - \frac{3999}{50000000}

x = - \frac{3999}{50000000}

The solution to the quadratic equation is:

x = - \frac{3999}{50000000}

3 x^{2} + 13 x + 10 = 0

1 x + 5 \geq - 16

(x^{8} y^{4})^{\frac{1}{10}} + 3 (x^{\frac{1}{5}} y^{\frac{1}{10}})^{4}

96 x^{2} + 12 = 0

10 - 2 (2 x - 4) = (3 x + 4) 2

What are the solutions to the equation x=0.25*(10^4x+0.8)^2 ?
The solutions to the equation x=0.25*(10^4x+0.8)^2 are x=-3999/50000000
Find the zeros of x=0.25*(10^4x+0.8)^2
The zeros of x=0.25*(10^4x+0.8)^2 are x=-3999/50000000