What are the solutions to the equation h^2-2h-2=0 ?

The solutions to the equation h^2-2h-2=0 are h=1+sqrt(3),h=1-sqrt(3)

Find the zeros of h^2-2h-2=0

The zeros of h^2-2h-2=0 are h=1+sqrt(3),h=1-sqrt(3)

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h^{2} - 2 h - 2 = 0

h = 1 + 3, h = 1 - 3

Decimal Notation

h = 2.73205 \dots, h = - 0.73205 \dots

Solution steps

h^{2} - 2 h - 2 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 2) = 23

h_{1, 2} = \frac{- ( - 2 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

h_{1} = \frac{- ( - 2 ) + 2 3}{2 \cdot 1}, h_{2} = \frac{- ( - 2 ) - 2 3}{2 \cdot 1}

h = \frac{- ( - 2 ) + 2 3}{2 \cdot 1} : 1 + 3

h = \frac{- ( - 2 ) - 2 3}{2 \cdot 1} : 1 - 3

The solutions to the quadratic equation are:

h = 1 + 3, h = 1 - 3

m^{2} - 4

- 5 c > 2

\frac{1 0 ^{8}}{1 0 ^{5}}

\frac{1 - \frac{s}{t}}{1 + \frac{s}{t}}

\frac{1}{3} (6 - 3 x) + \frac{1}{4} (x - 1) (x - 2) = \frac{x ^{2}}{4}

What are the solutions to the equation h^2-2h-2=0 ?
The solutions to the equation h^2-2h-2=0 are h=1+sqrt(3),h=1-sqrt(3)
Find the zeros of h^2-2h-2=0
The zeros of h^2-2h-2=0 are h=1+sqrt(3),h=1-sqrt(3)