What are the solutions to the equation 2x^2+3x-2=0 ?

The solutions to the equation 2x^2+3x-2=0 are x= 1/2 ,x=-2

Find the zeros of 2x^2+3x-2=0

The zeros of 2x^2+3x-2=0 are x= 1/2 ,x=-2

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2 x^{2} + 3 x - 2 = 0

x = \frac{1}{2}, x = - 2

Decimal Notation

x = 0.5, x = - 2

Solution steps

2 x^{2} + 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 2 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 2) = 5

x_{1, 2} = \frac{- 3 \pm 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 5}{2 \cdot 2}, x_{2} = \frac{- 3 - 5}{2 \cdot 2}

x = \frac{- 3 + 5}{2 \cdot 2} : \frac{1}{2}

x = \frac{- 3 - 5}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 2

2 x^{2} - 4 x - 6 = 0

x^{2} - 18 x + 81 = 5

∣ 2 x + 1 ∣ = 9

\frac{( a ^{- 2} b ^{3} ) ^{2}}{( a ^{3} b ^{2} ) ^{3}}

2 (x - 14) - x < 7 (x + 2) + x \leq x + 70

What are the solutions to the equation 2x^2+3x-2=0 ?
The solutions to the equation 2x^2+3x-2=0 are x= 1/2 ,x=-2
Find the zeros of 2x^2+3x-2=0
The zeros of 2x^2+3x-2=0 are x= 1/2 ,x=-2