What are the solutions to the equation -5x^2-19x+4=0 ?

The solutions to the equation -5x^2-19x+4=0 are x=-4,x= 1/5

Find the zeros of -5x^2-19x+4=0

The zeros of -5x^2-19x+4=0 are x=-4,x= 1/5

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- 5 x^{2} - 19 x + 4 = 0

x = - 4, x = \frac{1}{5}

Solution steps

- 5 x^{2} - 19 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 ( - 5 ) \cdot 4}{2 ( - 5 )}

(- 19)^{2} - 4 (- 5) \cdot 4 = 21

x_{1, 2} = \frac{- ( - 19 ) \pm 21}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 21}{2 ( - 5 )}, x_{2} = \frac{- ( - 19 ) - 21}{2 ( - 5 )}

x = \frac{- ( - 19 ) + 21}{2 ( - 5 )} : - 4

x = \frac{- ( - 19 ) - 21}{2 ( - 5 )} : \frac{1}{5}

The solutions to the quadratic equation are:

x = - 4, x = \frac{1}{5}

x + 5 \geq - 4

- 8 \leq 4 + 2 x \leq 14

s^{2} + 8 s - 125 = 0

x^{2} + 10 x + 5 = 0

(3 x + 5)^{2} - 39 = - 22

What are the solutions to the equation -5x^2-19x+4=0 ?
The solutions to the equation -5x^2-19x+4=0 are x=-4,x= 1/5
Find the zeros of -5x^2-19x+4=0
The zeros of -5x^2-19x+4=0 are x=-4,x= 1/5