What is (40}{n^2}\frac{n(n+1))/2 ?

The solution to (40}{n^2}\frac{n(n+1))/2 is (20(n+1))/n

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simplify (40}{n^2}\frac{n(n+1))/2

simplify

\frac{40}{n ^{2}} \frac{n ( n + 1 )}{2}

\frac{20 ( n + 1 )}{n}

Solution steps

\frac{40}{n ^{2}} \cdot \frac{n ( n + 1 )}{2}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{40 n ( n + 1 )}{n ^{2} \cdot 2}

Factor the number:

40 = 2 \cdot 20

= \frac{2 \cdot 20 n ( n + 1 )}{n ^{2} \cdot 2}

Cancel the common factor:

2

= \frac{20 n ( n + 1 )}{n ^{2}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

n^{2} = nn

= \frac{20 n ( n + 1 )}{nn}

Cancel the common factor:

n

= \frac{20 ( n + 1 )}{n}

m^{2} + 8 m + 16 = 45

c^{2} + 66 c - 67

6 x^{3} - 5 x^{2} - 12 x - 4

4 a^{2} - 9 c^{2}

- 2 x + 5 > 11

What is (40}{n^2}\frac{n(n+1))/2 ?
The solution to (40}{n^2}\frac{n(n+1))/2 is (20(n+1))/n