What are the solutions to the equation a^2-12a+18=0 ?

The solutions to the equation a^2-12a+18=0 are a=3(2+sqrt(2)),a=3(2-sqrt(2))

Find the zeros of a^2-12a+18=0

The zeros of a^2-12a+18=0 are a=3(2+sqrt(2)),a=3(2-sqrt(2))

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a^{2} - 12 a + 18 = 0

a = 3 (2 + 2), a = 3 (2 - 2)

Decimal Notation

a = 10.24264 \dots, a = 1.75735 \dots

Solution steps

a^{2} - 12 a + 18 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 18 = 62

a_{1, 2} = \frac{- ( - 12 ) \pm 6 2}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 12 ) + 6 2}{2 \cdot 1}, a_{2} = \frac{- ( - 12 ) - 6 2}{2 \cdot 1}

a = \frac{- ( - 12 ) + 6 2}{2 \cdot 1} : 3 (2 + 2)

a = \frac{- ( - 12 ) - 6 2}{2 \cdot 1} : 3 (2 - 2)

The solutions to the quadratic equation are:

a = 3 (2 + 2), a = 3 (2 - 2)

5 x^{2} - 19 x - 4

(- 6 x + 5) \cdot (x - 2) > 0

x^{2} - 26 x + 169 = - 13

99 - 13 (2 X - 10) = 4 (5 X - 9) - 5025

x^{2} - 2 x + \frac{2}{3} = 0

What are the solutions to the equation a^2-12a+18=0 ?
The solutions to the equation a^2-12a+18=0 are a=3(2+sqrt(2)),a=3(2-sqrt(2))
Find the zeros of a^2-12a+18=0
The zeros of a^2-12a+18=0 are a=3(2+sqrt(2)),a=3(2-sqrt(2))