What are the solutions to the equation (4x+5)^2=4(x+5)^2 ?

The solutions to the equation (4x+5)^2=4(x+5)^2 are x= 5/2 ,x=-5/2

Find the zeros of (4x+5)^2=4(x+5)^2

The zeros of (4x+5)^2=4(x+5)^2 are x= 5/2 ,x=-5/2

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(4 x + 5)^{2} = 4 (x + 5)^{2}

x = \frac{5}{2}, x = - \frac{5}{2}

Decimal Notation

x = 2.5, x = - 2.5

Solution steps

(4 x + 5)^{2} = 4 (x + 5)^{2}

Expand

(4 x + 5)^{2} : 16 x^{2} + 40 x + 25

Expand

4 (x + 5)^{2} : 4 x^{2} + 40 x + 100

16 x^{2} + 40 x + 25 = 4 x^{2} + 40 x + 100

Move

25

to the right side

16 x^{2} + 40 x = 4 x^{2} + 40 x + 75

Move

40 x

to the left side

16 x^{2} = 4 x^{2} + 75

Move

4 x^{2}

to the left side

12 x^{2} = 75

Divide both sides by

12

x^{2} = \frac{25}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{25}{4}, x = - \frac{25}{4}

\frac{25}{4} = \frac{5}{2}

- \frac{25}{4} = - \frac{5}{2}

x = \frac{5}{2}, x = - \frac{5}{2}

3 t - 1 < - 10 or 2 t + 4 \geq 6

3 x^{2} - 2 x + 10 = 0

2 x^{2} - 16 x + 24 = 0

- 4 x^{4} y^{2} + 8 y + 8

2^{- 4}

What are the solutions to the equation (4x+5)^2=4(x+5)^2 ?
The solutions to the equation (4x+5)^2=4(x+5)^2 are x= 5/2 ,x=-5/2
Find the zeros of (4x+5)^2=4(x+5)^2
The zeros of (4x+5)^2=4(x+5)^2 are x= 5/2 ,x=-5/2