What are the solutions to the equation 48x^2-82x+35=0 ?

The solutions to the equation 48x^2-82x+35=0 are x= 7/8 ,x= 5/6

Find the zeros of 48x^2-82x+35=0

The zeros of 48x^2-82x+35=0 are x= 7/8 ,x= 5/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

48 x^{2} - 82 x + 35 = 0

x = \frac{7}{8}, x = \frac{5}{6}

Decimal Notation

x = 0.875, x = 0.83333 \dots

Solution steps

48 x^{2} - 82 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 82 ) \pm ( - 82 ) ^{2} - 4 \cdot 48 \cdot 35}{2 \cdot 48}

(- 82)^{2} - 4 \cdot 48 \cdot 35 = 2

x_{1, 2} = \frac{- ( - 82 ) \pm 2}{2 \cdot 48}

Separate the solutions

x_{1} = \frac{- ( - 82 ) + 2}{2 \cdot 48}, x_{2} = \frac{- ( - 82 ) - 2}{2 \cdot 48}

x = \frac{- ( - 82 ) + 2}{2 \cdot 48} : \frac{7}{8}

x = \frac{- ( - 82 ) - 2}{2 \cdot 48} : \frac{5}{6}

The solutions to the quadratic equation are:

x = \frac{7}{8}, x = \frac{5}{6}

- 8 x < 16

54 = \frac{x ( x - 3 )}{2}

\frac{12 x ^{6} y ^{- 4} z ^{2}}{3 x ^{2} y ^{- 6} z ^{3}}

\frac{1}{16} x^{4} + 4 x^{2} + 64

\frac{1}{2} x^{2} + 3 x - 3.5

What are the solutions to the equation 48x^2-82x+35=0 ?
The solutions to the equation 48x^2-82x+35=0 are x= 7/8 ,x= 5/6
Find the zeros of 48x^2-82x+35=0
The zeros of 48x^2-82x+35=0 are x= 7/8 ,x= 5/6