What are the solutions to the equation x^2-22x=-121 ?

The solutions to the equation x^2-22x=-121 are x=11

Find the zeros of x^2-22x=-121

The zeros of x^2-22x=-121 are x=11

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x^{2} - 22 x = - 121

x = 11

Solution steps

x^{2} - 22 x = - 121

Move

121

to the left side

x^{2} - 22 x + 121 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 22 ) \pm ( - 22 ) ^{2} - 4 \cdot 1 \cdot 121}{2 \cdot 1}

(- 22)^{2} - 4 \cdot 1 \cdot 121 = 0

x_{1, 2} = \frac{- ( - 22 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 22 )}{2 \cdot 1}

\frac{- ( - 22 )}{2 \cdot 1} = 11

x = 11

The solution to the quadratic equation is:

x = 11

4 - \frac{1}{2}

(a + ib) (a - ib)

h^{2} + 6 h + 5

14 x - (3 x - 2) - [5 x + 2 - (x - 1)] = 0

3 (20) + 2 (18) \geq 93

What are the solutions to the equation x^2-22x=-121 ?
The solutions to the equation x^2-22x=-121 are x=11
Find the zeros of x^2-22x=-121
The zeros of x^2-22x=-121 are x=11