What is (a+ib)(a-ib) ?

The solution to (a+ib)(a-ib) is a^2+b^2

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simplify (a+ib)(a-ib)

simplify

(a + ib) (a - ib)

a^{2} + b^{2}

Solution steps

(a + ib) (a - ib)

Rewrite

a + ib

in standard complex form:

a + bi

Rewrite

a - ib

in standard complex form:

a - bi

= (a + bi) (a - bi)

Apply complex arithmetic rule:

(a + bi) (a - bi) = a^{2} + b^{2}

= a^{2} + b^{2}

h^{2} + 6 h + 5

14 x - (3 x - 2) - [5 x + 2 - (x - 1)] = 0

3 (20) + 2 (18) \geq 93

y, x^{3} - x^{2} + 2 x y - y^{2} = 0

5 x - 15 > - 65