What are the solutions to the equation 7x^2-13x-1=0 ?

The solutions to the equation 7x^2-13x-1=0 are x=(13+sqrt(197))/(14),x=(13-sqrt(197))/(14)

Find the zeros of 7x^2-13x-1=0

The zeros of 7x^2-13x-1=0 are x=(13+sqrt(197))/(14),x=(13-sqrt(197))/(14)

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7 x^{2} - 13 x - 1 = 0

x = \frac{13 + 197}{14}, x = \frac{13 - 197}{14}

Decimal Notation

x = 1.93111 \dots, x = - 0.07397 \dots

Solution steps

7 x^{2} - 13 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 7 ( - 1 )}{2 \cdot 7}

(- 13)^{2} - 4 \cdot 7 (- 1) = 197

x_{1, 2} = \frac{- ( - 13 ) \pm 197}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 197}{2 \cdot 7}, x_{2} = \frac{- ( - 13 ) - 197}{2 \cdot 7}

x = \frac{- ( - 13 ) + 197}{2 \cdot 7} : \frac{13 + 197}{14}

x = \frac{- ( - 13 ) - 197}{2 \cdot 7} : \frac{13 - 197}{14}

The solutions to the quadratic equation are:

x = \frac{13 + 197}{14}, x = \frac{13 - 197}{14}

4 x^{2} + 8 x + 20 = 0

2 x^{4} - 7 x^{3} + 3 x^{2} + 8 x - 4

3 X^{2} = - 99

(9 x)^{2}

4 a^{2} - 25

What are the solutions to the equation 7x^2-13x-1=0 ?
The solutions to the equation 7x^2-13x-1=0 are x=(13+sqrt(197))/(14),x=(13-sqrt(197))/(14)
Find the zeros of 7x^2-13x-1=0
The zeros of 7x^2-13x-1=0 are x=(13+sqrt(197))/(14),x=(13-sqrt(197))/(14)