What are the solutions to the equation -x^2+4x-11=0 ?

The solutions to the equation -x^2+4x-11=0 are x=2-sqrt(7)i,x=2+sqrt(7)i

Find the zeros of -x^2+4x-11=0

The zeros of -x^2+4x-11=0 are x=2-sqrt(7)i,x=2+sqrt(7)i

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- x^{2} + 4 x - 11 = 0

x = 2 - 7 i, x = 2 + 7 i

Solution steps

- x^{2} + 4 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) ( - 11 )}{2 ( - 1 )}

Simplify

4^{2} - 4 (- 1) (- 11) : 27 i

x_{1, 2} = \frac{- 4 \pm 2 7 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 7 i}{2 ( - 1 )}, x_{2} = \frac{- 4 - 2 7 i}{2 ( - 1 )}

x = \frac{- 4 + 2 7 i}{2 ( - 1 )} : 2 - 7 i

x = \frac{- 4 - 2 7 i}{2 ( - 1 )} : 2 + 7 i

The solutions to the quadratic equation are:

x = 2 - 7 i, x = 2 + 7 i

- 8 - 56 a

3 t^{2} + 11 t - 20

x^{2} - 3 x + 18 = 0

\frac{3}{4} \cdot 24

8 x^{4} + 28 x^{3} + 20 x^{2}

What are the solutions to the equation -x^2+4x-11=0 ?
The solutions to the equation -x^2+4x-11=0 are x=2-sqrt(7)i,x=2+sqrt(7)i
Find the zeros of -x^2+4x-11=0
The zeros of -x^2+4x-11=0 are x=2-sqrt(7)i,x=2+sqrt(7)i