What are the solutions to the equation x^2-3x+18=0 ?

The solutions to the equation x^2-3x+18=0 are x= 3/2+i(3sqrt(7))/2 ,x= 3/2-i(3sqrt(7))/2

Find the zeros of x^2-3x+18=0

The zeros of x^2-3x+18=0 are x= 3/2+i(3sqrt(7))/2 ,x= 3/2-i(3sqrt(7))/2

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x^{2} - 3 x + 18 = 0

x = \frac{3}{2} + i \frac{3 7}{2}, x = \frac{3}{2} - i \frac{3 7}{2}

Solution steps

x^{2} - 3 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

Simplify

(- 3)^{2} - 4 \cdot 1 \cdot 18 : 37 i

x_{1, 2} = \frac{- ( - 3 ) \pm 3 7 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3 7 i}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 3 7 i}{2 \cdot 1}

x = \frac{- ( - 3 ) + 3 7 i}{2 \cdot 1} : \frac{3}{2} + i \frac{3 7}{2}

x = \frac{- ( - 3 ) - 3 7 i}{2 \cdot 1} : \frac{3}{2} - i \frac{3 7}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{3 7}{2}, x = \frac{3}{2} - i \frac{3 7}{2}

\frac{3}{4} \cdot 24

8 x^{4} + 28 x^{3} + 20 x^{2}

2 (2 + x) - (6 - 7 x) = 133 x - (1 + 4 x)

3^{e} = x

(x + 3) (x - 2) \leq 0

What are the solutions to the equation x^2-3x+18=0 ?
The solutions to the equation x^2-3x+18=0 are x= 3/2+i(3sqrt(7))/2 ,x= 3/2-i(3sqrt(7))/2
Find the zeros of x^2-3x+18=0
The zeros of x^2-3x+18=0 are x= 3/2+i(3sqrt(7))/2 ,x= 3/2-i(3sqrt(7))/2