What are the solutions to the equation 3x^2-2x+4=-4x+9 ?

The solutions to the equation 3x^2-2x+4=-4x+9 are x=1,x=-5/3

Find the zeros of 3x^2-2x+4=-4x+9

The zeros of 3x^2-2x+4=-4x+9 are x=1,x=-5/3

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3 x^{2} - 2 x + 4 = - 4 x + 9

x = 1, x = - \frac{5}{3}

Solution steps

3 x^{2} - 2 x + 4 = - 4 x + 9

Move

9

to the left side

3 x^{2} - 2 x - 5 = - 4 x

Move

4 x

to the left side

3 x^{2} + 2 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 5) = 8

x_{1, 2} = \frac{- 2 \pm 8}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 8}{2 \cdot 3}, x_{2} = \frac{- 2 - 8}{2 \cdot 3}

x = \frac{- 2 + 8}{2 \cdot 3} : 1

x = \frac{- 2 - 8}{2 \cdot 3} : - \frac{5}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{5}{3}

5 (x - 4)^{2} = 125

p^{2} + 8 p + 10 = 0

\frac{1}{3} x = 3

x^{2} y^{4} - x^{5} y^{2}

16 x^{2} + 56 x y + 49 y^{2}

What are the solutions to the equation 3x^2-2x+4=-4x+9 ?
The solutions to the equation 3x^2-2x+4=-4x+9 are x=1,x=-5/3
Find the zeros of 3x^2-2x+4=-4x+9
The zeros of 3x^2-2x+4=-4x+9 are x=1,x=-5/3