What are the solutions to the equation 4x^2-12x-16=0 ?

The solutions to the equation 4x^2-12x-16=0 are x=4,x=-1

Find the zeros of 4x^2-12x-16=0

The zeros of 4x^2-12x-16=0 are x=4,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} - 12 x - 16 = 0

x = 4, x = - 1

Solution steps

4 x^{2} - 12 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 ( - 16 )}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 (- 16) = 20

x_{1, 2} = \frac{- ( - 12 ) \pm 20}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 20}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 20}{2 \cdot 4}

x = \frac{- ( - 12 ) + 20}{2 \cdot 4} : 4

x = \frac{- ( - 12 ) - 20}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

x = 4, x = - 1

y^{2} - y = 6

- 7 d - 22 = 4 d

y^{2} - 12 y + 36

x^{2} + 5 x + 13 = 0

\frac{6}{5 x ^{2} y} + \frac{5}{10 x y ^{2}}

What are the solutions to the equation 4x^2-12x-16=0 ?
The solutions to the equation 4x^2-12x-16=0 are x=4,x=-1
Find the zeros of 4x^2-12x-16=0
The zeros of 4x^2-12x-16=0 are x=4,x=-1