What are the solutions to the equation x^2+5x+13=0 ?

The solutions to the equation x^2+5x+13=0 are x=-5/2+i(3sqrt(3))/2 ,x=-5/2-i(3sqrt(3))/2

Find the zeros of x^2+5x+13=0

The zeros of x^2+5x+13=0 are x=-5/2+i(3sqrt(3))/2 ,x=-5/2-i(3sqrt(3))/2

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x^{2} + 5 x + 13 = 0

x = - \frac{5}{2} + i \frac{3 3}{2}, x = - \frac{5}{2} - i \frac{3 3}{2}

Solution steps

x^{2} + 5 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

Simplify

5^{2} - 4 \cdot 1 \cdot 13 : 33 i

x_{1, 2} = \frac{- 5 \pm 3 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 3 3 i}{2 \cdot 1}, x_{2} = \frac{- 5 - 3 3 i}{2 \cdot 1}

x = \frac{- 5 + 3 3 i}{2 \cdot 1} : - \frac{5}{2} + i \frac{3 3}{2}

x = \frac{- 5 - 3 3 i}{2 \cdot 1} : - \frac{5}{2} - i \frac{3 3}{2}

The solutions to the quadratic equation are:

x = - \frac{5}{2} + i \frac{3 3}{2}, x = - \frac{5}{2} - i \frac{3 3}{2}

\frac{6}{5 x ^{2} y} + \frac{5}{10 x y ^{2}}

(x + 9)^{2} = - 64

3 (x + 3)^{2} - 6 = 0

- 3 x^{2} + 9 x - 6 = 0

9 v^{2} - 64 = 0

What are the solutions to the equation x^2+5x+13=0 ?
The solutions to the equation x^2+5x+13=0 are x=-5/2+i(3sqrt(3))/2 ,x=-5/2-i(3sqrt(3))/2
Find the zeros of x^2+5x+13=0
The zeros of x^2+5x+13=0 are x=-5/2+i(3sqrt(3))/2 ,x=-5/2-i(3sqrt(3))/2