What are the solutions to the equation y^2-y=6 ?

The solutions to the equation y^2-y=6 are y=3,y=-2

Find the zeros of y^2-y=6

The zeros of y^2-y=6 are y=3,y=-2

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y^{2} - y = 6

y = 3, y = - 2

Solution steps

y^{2} - y = 6

Move

6

to the left side

y^{2} - y - 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 6) = 5

y_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 1}, y_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 1}

y = \frac{- ( - 1 ) + 5}{2 \cdot 1} : 3

y = \frac{- ( - 1 ) - 5}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

y = 3, y = - 2

- 7 d - 22 = 4 d

y^{2} - 12 y + 36

x^{2} + 5 x + 13 = 0

\frac{6}{5 x ^{2} y} + \frac{5}{10 x y ^{2}}

(x + 9)^{2} = - 64

What are the solutions to the equation y^2-y=6 ?
The solutions to the equation y^2-y=6 are y=3,y=-2
Find the zeros of y^2-y=6
The zeros of y^2-y=6 are y=3,y=-2