What are the solutions to the equation 3x^2+4=40 ?

The solutions to the equation 3x^2+4=40 are x=2sqrt(3),x=-2sqrt(3)

Find the zeros of 3x^2+4=40

The zeros of 3x^2+4=40 are x=2sqrt(3),x=-2sqrt(3)

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3 x^{2} + 4 = 40

x = 23, x = - 23

Decimal Notation

x = 3.46410 \dots, x = - 3.46410 \dots

Solution steps

3 x^{2} + 4 = 40

Move

4

to the right side

3 x^{2} = 36

Divide both sides by

3

x^{2} = 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 12, x = - 12

12 = 23

- 12 = - 23

x = 23, x = - 23

(3 x - 8) (x - 7) = 0

\frac{4}{5} - \frac{1}{4}

∣ x + 1 ∣ \geq \frac{x - 1}{3}

x + 5 = 4

21 \cdot 7

What are the solutions to the equation 3x^2+4=40 ?
The solutions to the equation 3x^2+4=40 are x=2sqrt(3),x=-2sqrt(3)
Find the zeros of 3x^2+4=40
The zeros of 3x^2+4=40 are x=2sqrt(3),x=-2sqrt(3)