What are the solutions to the equation (3x-8)(x-7)=0 ?

The solutions to the equation (3x-8)(x-7)=0 are x= 8/3 ,x=7

Find the zeros of (3x-8)(x-7)=0

The zeros of (3x-8)(x-7)=0 are x= 8/3 ,x=7

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(3 x - 8) (x - 7) = 0

x = \frac{8}{3}, x = 7

Solution steps

(3 x - 8) (x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 8 = 0 or x - 7 = 0

Solve

3 x - 8 = 0 : x = \frac{8}{3}

Solve

x - 7 = 0 : x = 7

The solutions to the quadratic equation are:

x = \frac{8}{3}, x = 7

\frac{4}{5} - \frac{1}{4}

∣ x + 1 ∣ \geq \frac{x - 1}{3}

x + 5 = 4

21 \cdot 7

8 c - 7 - (3 c - 11) = 5 (3 c + 11) + 6 c

What are the solutions to the equation (3x-8)(x-7)=0 ?
The solutions to the equation (3x-8)(x-7)=0 are x= 8/3 ,x=7
Find the zeros of (3x-8)(x-7)=0
The zeros of (3x-8)(x-7)=0 are x= 8/3 ,x=7