What are the solutions to the equation 2x^2+2x=0 ?

The solutions to the equation 2x^2+2x=0 are x=0,x=-1

Find the zeros of 2x^2+2x=0

The zeros of 2x^2+2x=0 are x=0,x=-1

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2 x^{2} + 2 x = 0

x = 0, x = - 1

Solution steps

2 x^{2} + 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

2^{2} - 4 \cdot 2 \cdot 0 = 2

x_{1, 2} = \frac{- 2 \pm 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 2 + 2}{2 \cdot 2}, x_{2} = \frac{- 2 - 2}{2 \cdot 2}

x = \frac{- 2 + 2}{2 \cdot 2} : 0

x = \frac{- 2 - 2}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = 0, x = - 1

- 3 x > 9

\frac{( 1 + 5 )}{2}

(1 - 2 x)^{2} - 12 = 0

lo g_{6} (9) + lo g_{6} (4)

m + 11 < 3 or \frac{m}{3} > - 2

What are the solutions to the equation 2x^2+2x=0 ?
The solutions to the equation 2x^2+2x=0 are x=0,x=-1
Find the zeros of 2x^2+2x=0
The zeros of 2x^2+2x=0 are x=0,x=-1