What are the solutions to the equation (1-2x)^2-12=0 ?

The solutions to the equation (1-2x)^2-12=0 are x=-(2sqrt(3)-1)/2 ,x=(2sqrt(3)+1)/2

Find the zeros of (1-2x)^2-12=0

The zeros of (1-2x)^2-12=0 are x=-(2sqrt(3)-1)/2 ,x=(2sqrt(3)+1)/2

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(1 - 2 x)^{2} - 12 = 0

x = - \frac{2 3 - 1}{2}, x = \frac{2 3 + 1}{2}

Decimal Notation

x = - 1.23205 \dots, x = 2.23205 \dots

Solution steps

(1 - 2 x)^{2} - 12 = 0

Move

12

to the right side

(1 - 2 x)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

1 - 2 x = 12 : x = - \frac{2 3 - 1}{2}

Solve

1 - 2 x = - 12 : x = \frac{2 3 + 1}{2}

The solutions to the quadratic equation are:

x = - \frac{2 3 - 1}{2}, x = \frac{2 3 + 1}{2}

lo g_{6} (9) + lo g_{6} (4)

m + 11 < 3 or \frac{m}{3} > - 2

f (1) \frac{( x ^{2} - 2 )}{x ^{2} + x + 1}

(x + 2) (x - 4) + 7 (x - 4)

- 2.17 = 0.35 r

What are the solutions to the equation (1-2x)^2-12=0 ?
The solutions to the equation (1-2x)^2-12=0 are x=-(2sqrt(3)-1)/2 ,x=(2sqrt(3)+1)/2
Find the zeros of (1-2x)^2-12=0
The zeros of (1-2x)^2-12=0 are x=-(2sqrt(3)-1)/2 ,x=(2sqrt(3)+1)/2