What are the solutions to the equation x^2+26x=0 ?

The solutions to the equation x^2+26x=0 are x=0,x=-26

Find the zeros of x^2+26x=0

The zeros of x^2+26x=0 are x=0,x=-26

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x^{2} + 26 x = 0

x = 0, x = - 26

Solution steps

x^{2} + 26 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 26 \pm 2 6 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

2 6^{2} - 4 \cdot 1 \cdot 0 = 26

x_{1, 2} = \frac{- 26 \pm 26}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 26 + 26}{2 \cdot 1}, x_{2} = \frac{- 26 - 26}{2 \cdot 1}

x = \frac{- 26 + 26}{2 \cdot 1} : 0

x = \frac{- 26 - 26}{2 \cdot 1} : - 26

The solutions to the quadratic equation are:

x = 0, x = - 26

9 x^{2} - 63 x = 0

3 x^{2} + 4 x + x

(x - 2) (x - 1) = 2

x y - 7 x + 7 y - 49

- 2 x - 5 \leq 3 x - 5

What are the solutions to the equation x^2+26x=0 ?
The solutions to the equation x^2+26x=0 are x=0,x=-26
Find the zeros of x^2+26x=0
The zeros of x^2+26x=0 are x=0,x=-26