What are the solutions to the equation x^2-10x-22=0 ?

The solutions to the equation x^2-10x-22=0 are x=5+sqrt(47),x=5-sqrt(47)

Find the zeros of x^2-10x-22=0

The zeros of x^2-10x-22=0 are x=5+sqrt(47),x=5-sqrt(47)

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x^{2} - 10 x - 22 = 0

x = 5 + 47, x = 5 - 47

Decimal Notation

x = 11.85565 \dots, x = - 1.85565 \dots

Solution steps

x^{2} - 10 x - 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 22 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 22) = 247

x_{1, 2} = \frac{- ( - 10 ) \pm 2 47}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 47}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 47}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 47}{2 \cdot 1} : 5 + 47

x = \frac{- ( - 10 ) - 2 47}{2 \cdot 1} : 5 - 47

The solutions to the quadratic equation are:

x = 5 + 47, x = 5 - 47

\frac{2 π}{( \frac{2}{3} )}

2 x^{2} - 3 x = 2

\frac{32}{5}

\frac{147}{4} - x = 5

- 2 x^{2} - 24 x - 322 = 0

What are the solutions to the equation x^2-10x-22=0 ?
The solutions to the equation x^2-10x-22=0 are x=5+sqrt(47),x=5-sqrt(47)
Find the zeros of x^2-10x-22=0
The zeros of x^2-10x-22=0 are x=5+sqrt(47),x=5-sqrt(47)