-2x^2+8x<0

Solution

- 2 x^{2} + 8 x < 0

x < 0 or x > 4

Interval Notation

(- \infty, 0) \cup (4, \infty)

Solution steps

- 2 x^{2} + 8 x < 0

Rewrite in standard form

- x^{2} + 4 x < 0

Factor

- x^{2} + 4 x : - x (x - 4)

- x (x - 4) < 0

Multiply both sides by

- 1

(reverse the inequality)

(- x (x - 4)) (- 1) > 0 \cdot (- 1)

Simplify

x (x - 4) > 0

Identify the intervals

x < 0 or x > 4

\frac{( 6.9 - 4.8 )}{4 - 5}

x^{2} - 9 x + 25 = 0

2 x^{2} + 8 x + 2 = 0

- 12 v - 9 + 7 v = 26

6 (x - 1) > 18