What is (2x-1)/(2x+1)<= (x+1)/(x-1) ?

The solution to (2x-1)/(2x+1) 1

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(2x-1)/(2x+1)<= (x+1)/(x-1)

\frac{2 x - 1}{2 x + 1} \leq \frac{x + 1}{x - 1}

- \frac{1}{2} < x \leq 0 or x > 1

Interval Notation

(- \frac{1}{2}, 0] \cup (1, \infty)

Decimal Notation

- 0.5 < x \leq 0 or x > 1

Solution steps

\frac{2 x - 1}{2 x + 1} \leq \frac{x + 1}{x - 1}

Rewrite in standard form

\frac{x}{( x - 1 ) ( 2 x + 1 )} \geq 0

Identify the intervals

- \frac{1}{2} < x \leq 0 or x > 1

- 2 x^{2} + 8 x < 0

\frac{( 6.9 - 4.8 )}{4 - 5}

x^{2} - 9 x + 25 = 0

2 x^{2} + 8 x + 2 = 0

- 12 v - 9 + 7 v = 26

What is (2x-1)/(2x+1)<= (x+1)/(x-1) ?
The solution to (2x-1)/(2x+1)<= (x+1)/(x-1) is -1/2 <x<= 0\lor x>1